The Last Practice

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 9185 Accepted Submission(s): 1947

Problem Description

Tomorrow is contest day, Are you all ready?

We have been training for 45 days, and all guys must be tired.But , you are so lucky comparing with many excellent boys who have no chance to attend the Province-Final.

Now, your task is relaxing yourself and making the last practice. I guess that at least there are 2 problems which are easier than this problem.

what does this problem describe?

Give you a positive integer, please split it to some prime numbers, and you can got it through sample input and sample output.

Input

Input file contains multiple test case, each case consists of a positive integer n(1<n<65536), one per line. a negative terminates the input, and it should not to be processed.

Output

For each test case you should output its factor as sample output (prime factor must come forth ascending ), there is a blank line between outputs.

Sample Input

      60 12 -1 

Sample Output

      Case 1. 2 2 3 1 5 1 Case 2. 2 2 3 1 
Hint
 60=2^2*3^1*5^1 

本地编译器优化的太多也不好，一个语句分号前面多了个逗号竟然也可以编译，第一次妥妥的CE了

代码：

#include
     
      #include
      
       #include
       
        #include
        #include
         
          using namespace std;int main(void){    int n,i,t=0;    while (cin>>n&&n>=0)    {        t++;        if(t!=1)            cout<
          
            list; for (i=2; i<=n; i++) { while (n%i==0) { list[i]++; n/=i; } } map
           
            ::iterator it; printf("Case %d.\n",t); for (it=list.begin(); it!=list.end(); it++) { cout<
            
             first<<" "<
             
              second<<" ";//这题有毒竟然不按套路出牌，最后也要有空格 } cout<

转载于:https://www.cnblogs.com/Blackops/p/5356431.html

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